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In this video, I'm going to present the
rather technical derivation of an

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important equation of quantum theory.
The continuity equation for probability,

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which both relies on the Borne
interpretation of quantum theory and also

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serves as a sort of safety check for it.
Because it establishes the conservation of

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probability.
The idea here is that, even though we

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cannot see with certainty where exactly
our quantum particle is located, we can

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certainly, we can be sure that it's
located somewhere in space so if we

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perform a measurement and look for the
particle everywhere, we're going to find

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it with a probability equal to one.
And this total probability never becomes

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smaller than one and certainly cannot
become larger than one, so it is

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conserved.
And this simple conservation law gives

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rise to this continuity equation that
we're going to derive.

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Now, the form of this equation is actually
not specific to quantum theory, and it

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appears in many different fields of
physics.

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So raw here is the density of a
conservative quantity.

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In our case this is the probability
density, which per the born rule is equal

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to the absolute value of the wave function
squared.

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And g here is the probability current,
which we actually are going to derive.

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So to see that this equation indeed
describes some sort of a conservation

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law,.
Let me consider an arbitrary volume in

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space.
So let's say this is a volume V, and let

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me also denote the surface encircling this
volume as dV.

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And let me be interested in the
probability of finding the particle of my

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quantum particle inside this volume.
So this probability, let me call it P sub

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v, is going to be an integral of the
probability density, which appears here

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over this volume.
Now to see to look at the dynamics of this

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probability with time, let me integrate
both sides of this equation over the

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volume.
Well, the right hand side here is zero,

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there is not much to integrate, but the
first term is going to give me just dp

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over dt, and the second term is going to
be an integral of the diversions of g.

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And everything, the sum of these two terms
is equal to 0.

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Now at this stage, I can use the Gauss's
theorem to handle the second term, which

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tells me that the integral of a full
diversion, so for a volume, is equal to a

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flux of the vector of which I calculated
diversions, through the surface

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surrounding my volume.
So this is my dv.

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So in ds here is an elementary An
elementary surface element, with the

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vector pointing, outwards.
So I'm sure, some of you have already

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seen, the Guassian theorem, let's say, in
the theory of electromagnetism.

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But if, you forgot about it, or you have
never seen it.

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So let me just mention that this Gauss,
theorem is in some sense, similar to the

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simple identity that we oftentimes use for
usual integral, so let's see if we have an

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integral between a and b or the full
derivative of a function df dx, so we can

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write the result in the result as f of b
minus f of So essentially in this case we

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have a one-dimensional segment from a to
b, or we, we integrate and of we have a

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full derivative we can only focus on the
end points.

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So that's the only thing which answer is
the final result.

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So likewise if we have more complicated
integral now, an integral over, over three

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dimensional volume but of a full
derivative, which it divergence.

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E is, so instead of having two boundary
values we have a, a surface integral going

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through this surface through this dv.
So in some sense this dv is similar to a

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and b, so the volume is similar to the
segment of between a and b and the full

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derivative df.
Over the X, is similar to the divergence

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of G.
So what we actually have established here

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is the derivative, what we call it P dot
of the probability of finding a particle

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in the volume V is equal to minus the flux
of the probability current again, we're

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going to derive it a little later.
Through the surface surrounding this

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volume and let's see if we have a current
say going outwards here luckily, so that

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only so that there is forms as small angle
with the ds so then this g.ds is positive

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which corresponds to the negative change
in the probability so and it makes sense

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because, it means that.
The current carries away the probability,

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and the probability of finding a particle
inside decreases.

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So if we, on the other hand, have the
current going inside, the probability is

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going to increase.
So in order for me to prove the continuity

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equation in the form I just formulated,
let me calculate directly the probability

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of finding my particle in the volume v
over time using the boron, rule and, the

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boron rule basically implies that I
calculate the derivative of this integral

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of the volume of the absolute value of my
wave function squared, and the absolute

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value can vary in, of course by definition
as a product of the wave function and its

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complex integrated everything and degraded
over the volume.

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So now if I apply this derivative to this
product, I can write it as psi star dot

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psi plus psi star psi dot.
So in order for me to simplify it further

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Let me just use the Schrodinger equation
in it's center form, which actually

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appears on the logo of our, of our course.
So, and express the psi dot from here as

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simply minus i over H bar doing on, acting
on sine.

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So I just divided it by H bar, and
multiplied both sides with the imaginary

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constant I.
So I can also drive the same equation

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with, for psi star dot and the since
Hamiltonian is sort of real cause the

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kinetic potential is just going to be plus
I over H bar, H acting on psi.

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Now my H here is a combination of kinetic
energy and potential energy.

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So kinetic energy is sort of an involved
operator which is the momentum squared and

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potential energy is just multiplication,
it just multiplies my wave function.

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So if I put everything together, what I
will find is, the following, for P V dot,

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so I'm going to have here instead of psi
star dot, I'm going to have this guy, so

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I.
H bar h psi, and here we have minus i h

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bar psi star h psi.
So if h were a number so these 2 terms

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would cancel each other out.
And it does happen, as a matter of fact

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for the potential energy draw So if, so
this H can actually be expre-, replaced

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with a kinetic energy.
But there's no consolation necessarily for

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the kinetic energy because again, this is
an operator which acts on different

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functions here and here.
And, this operator is equal to just p

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squared over 2m, or minus h squared over
2m Laplacian.

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So we should write as delta number
squared.

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So again, putting everything together, so
what I have is minus i h bar 2 m, which I

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can factor out outside the integral.
And in the brackets I'm going to have the

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Laplacian number squared psi start and psi
minus psi star number squared, squared

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psi.
So the last step here is to integrate this

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expression by parts, and if I do so
essentially by moving this delta from here

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to here and from here back to here, so I
see that these terms become identical and

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cancel each other out.
And the only term which survives is, the

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full derivative of delta up side star.
Psi minus complex conjugated.

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So, And this whole thing, well, times this
coefficient, is exactly the current that

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we have been looking for because, again,
we ended up with the full derivative of a

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vector integrated over the volume.
So we can write it as minus an integral of

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sum G over DS over the distribute, this
sort of encircling, encircling our volume.

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So finally, we can just collect everything
from this expression and write the final

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expression for the current, which I will
arrive in the full length forum, which is,

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1/2 side star, p, over m, edging on side,
plus complex country.

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So, the reason I can write like this is
because P is an operator, which is equal

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to minus I H bar.
Nebla and this minus i h and r, hr nebla

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appears here, and so if we look at this 5
expressions, we see that the symmetric

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effect makes sort of intuitive sense,
because in classical physics, a classical

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current associated with the density, rho,
is simply the density times the velocity

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with which it moves.
Now, here in quantum mechanics the

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momentum is an operator so velocity which
is momentum divided by m is also an

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operator.
And this operator sort of acts on the

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density which is which is rho is psi star
psi.

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So and so this is the final result which
connects the change in the probability of

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finding a particle in the volume v with
the flux of a certain probability current

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flowing through the surface.
