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Now, we're going to put to work the main
equation of Quantum Mechanics, the

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Schrodinger equation, and use it to solve
a very interesting problem that will also

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illustrate why quantum mechanical effects
are not important in our everyday lives

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while being essential when we're deal with
atomic link scales.

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The question we're going to ask is what
happens if when enforced a particle like

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solution in our Quantum Mechanical
problem.

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So basically, what it means is that we
postulate, let's postulate that the t

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equals 0, at initial moment of time, t
equals 0, we have the wave-function such

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as this, which is called Gaussian
wave-packet.

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And this wave-function it, it basically
describes the particle which is localized

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in space around 0 so it's a typical
Gaussian around 0 and this spread out of

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this Gaussian is a form of g, which is the
parameter of the [unknown] in some

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coefficient is not very important at this
stage.

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Now, the calculation that we are going to
present is essentially to the evolution of

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this initial condition with time, under
the action of the Schrodinger equation,

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and it's a big technical question.
So, for those of you who are not

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interested in technical details, I would
like just to present the final answers so

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that you can understand the bottom line
without going into technicalities.

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And so, the final answer is here, so here,
we have the wave-function as the function

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of time models of it squared.
So, we describe initial condition

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particles and as we will see, this psi
squared is, has the same Gaussian form as

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the regional wave-function.
But the difference here is that the

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parameter d, which describes its
spreading, it increases with time.

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And it increases with time as 1 plus t
squared over some tau squared, where tau

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squared is this typical time scale at
which the spreading occurs.

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So for now, look at this dependence of psi
squared on x.

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And as time goes by, we will see a more
and more uniform density.

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So eventually, it will be almost flat.
Now, this basically implies that the

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particle light solution, this type of wave
[unknown] is unstable in quantum

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mechanics.
So but the important thing is the time

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scale itself that we, at which this
spreading occurs.

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And let us estimate this time scale for
two sort of diametrically opposite cases.

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So, one case will be the case of an
electron and microscopic elementary

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particle with a mass of about 10 to minus
27 grams and let's assume that it's

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localized on atomic length scales
[unknown] 10 to minus eight centimeters.

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So, if we plug in the numbers, what we're
going to, to see is the typical time scale

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which the spreading of the localization
radius, if you want of this electron

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doubles is in the order of 10 to the minus
16th seconds which is an extremely short

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time scale hardly observable in any
experiment.

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Now, if we take on the contrary in a
microscopic object, let's say, a typical

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human being, which is also described by
Laws of Quantum Mechanics so the

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difference will be quite noticeable.
So here, while the mass, of course, of the

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microscopic object here will be around,
let's say, 50 kilograms, and let's say

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want to be localized on a distance of
total 1 centimeter.

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Now, if we now plug in the numbers into
this equation, what we're going to see is

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that the typical time scale at which sort
of quantum delocalization of human being

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recursed is a [unknown] 10 to, to, to 30
to plus 30 seconds.

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So, to put this number in perspective, so
this is equal to the 10 to the 23 years or

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10 to the 13th, 10 trillion lifetimes of
the universe years.

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So basically, it's in some sense,
meaningless number.

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Sp, it's a number which never, which is
never relevant in any realistic

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circumstances so we should not be worrying
too much about being quantum delocalized

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due to quantum mechanical effects.
And if we now look at different time

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scales for various objects that we're
dealing in, in our everyday lives, we're

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going to see that essentially, for all
these objects, even the smallest ones, we

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can safely say that quantum mechanical
effects are completely irrelevant.

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But at the moment, we're going to, we're
going to go to a fundamental microscopic

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run scales is going to change very
significantly.

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Now, I'm going to actually derive the main
result that they presented in the previous

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slide about the revolution of the Gaussian
wave predicate.

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And as I mentioned to you, this derivation
is a bit on the technical side so those of

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you who are not really interested in this
technicalities may just skip it towards

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the end of this lecture.
But those who want to actually learn the

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technical part of Quantum Mechanics, which
is the main part of Quantum Mechanics,

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should pay attention perhaps to derive it
on your own.

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Now, the main element of the solution is
the decomposition of the original the

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initial condition of this wave-packet Into
the plane-waves.

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So, the plane-waves are presented here.
So, sort of as an intuition as to why we

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want to do something like this, we should
recall that the Schrodinger's equation was

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deduced or derived from almost by
construction to describe waves rather than

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particles.
So, the initial condition that we can

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choose is in some sense, an arbitrary
function.

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So, there's actually no reason why it
would be a convenient solution to, to

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anything.
So, while the plane-waves are indeed the

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solutions, and so by the composing this
function or any initial condition for this

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matrix, this plane-waves, we actually
simplify things a lot, as we will see

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later.
From the mathematical point of view, this

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decomposition is nothing but a Fourier
transform of this Gaussian wave-function,

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into the into the harmonic function, into
this cosines and sines.

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And we know very well how to do this
decomposition but before we before we go

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to it, I would like to remind you of the
following identity for Gaussian integral

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which we, which actually we're going to
use at least three times in this

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deliberation, in different topics.
So, if we have an exponential of a

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quadratic function with some coefficients
alpha and beta here, so the integral from

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minus infinity to plus infinity is
well-known and it's given by this

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equation.
So, we're going to just use it later on.

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Now the reasons UNKNOWN] in this, this
stage of the derivation is because the

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Fourier transform or in other words this,
this Fourier harmonics which in the

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context of Quantum Mechanics are called
wave-function in the momentum space are

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determined exactly by this type of
Gaussian integral.

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Because what we have to do in order to do
in [unknown] on this phi of p, we have to

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take avoid the integral of this of this
exponential e to the power of minus x

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squared over 2d squared with, with this e
to the power minus i over h bar px.

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And if we look at this integral, so, and
compare it with this Gaussian expression,

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we will, we will see that alpha here is,
is equal to 1 over 2 d squared.

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And beta is equal to minus i h bar p.
So if we use now this formula, so beta

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squared is equal to minus p squared over h
squared and divided by 4 alpha will give

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us the Fourier expression.
So, if I completely ignore the overall

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coefficient, it's not really important for
the following.

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So, now let me just erase this and get rid
of this Gaussian integral.

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So now we're going to interpret, actually,
this Fourier transform in an interesting

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way.
So the reason we have constructed this

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initial condition in this form, was
because we wanted to localize our particle

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sort of in the certain length scales of
order d.

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So, the uncertainty of our initial
condition in, in, in the real space is of

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order d, but by looking at this sort of
wave-function in the momentum space, we

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see that the uncertainty in momentum delta
p is a [unknown] h bar over d.

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So, it's inverse proportional to the, a
localization distance in real space.

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And so, this sort of dual relation, so the
more it's localized in real space, the

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less it's localized in the momentum space
and vice-versa is a particular

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manifestation of what is known as the
general Heisenberg uncertainty of

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principle, which is which is written here.
So, that in, in general, whatever wave

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function you have, whatever quantum state
you possibly can construct, there is

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always a constraint that the uncertainty
in position, then the uncertainty in

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momentum is larger or equal than h bar, h
bar being the plane constant.

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So now, we're in the position to solve the
main technical problem that we formulated

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in the beginning called this, this segment
that is to solve the Schrodinger equation

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the free Schrodinger equation here.
So, the [unknown] here is just p squared

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over 2m with initial condition written as
so.

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So, instead of writing it as a Gaussian
real space, we write it as a linear

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combination of plane -waves that was
basically the Fourier transform in the

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previous slide.
Now, in order to write the time-dependent

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wave-function we need to take into account
two simple circumstances.

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The first circumstance is the fact that
the Schrodinger equation, the fact that

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the Schrodinger equation is a linear
equation.

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Which implies that if we have several
solutions to this equation, psi 1, psi 2,

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psi 3, etc.
Their sum is also a solution, with the

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initial condition being simply the sum of
the corresponding initial conditions.

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Now, the second circumstance is we have to
recall that a plane wave written as so is,

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is an, is an eta solution to the
Schrodinger equation.

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In some sense, we have constructed
Schrodinger equation such that it would

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give us this guy as a solution.
And here, the epsilon of p is the energy

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of the electron, the energy of free
electron and simply equal to p squared

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over 2m.
Now if we take a look at the initial

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condition again written in this form, we
see that it's an integral over momentum,

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but integral is a sum, in some sense which
just happens to be in infinite psi.

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So, we can use the fact that a Schrodinger
equation is a linear equation and write

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psi of x and t, the full solution as so.
So basically, all we have to do is to

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replace this plane-wave at, at t equals 0
with the plane-wave at a finite time with

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epsilon of p being p squared over 2m.
And so, to write now the wave-function in

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a more convenient way so what remains now
is to calculate the Gaussian integral over

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momentum.
And it can be done again using the same

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identity that we used in the previous
slide but now, the parameter alpha here is

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going to be d squared over 2h squared plus
i, it divided by 2m h bar and the

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parameter beta now is ix over h bar.
So again, if we use the same identity,

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what we get is the, the following
expression for the wave-function.

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We see that this expression is an
intrinsically complex function but if

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we're interested just in determining the
density of our particles or where the

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particle is located, so the only thing
which matters, as I mentioned already and

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we'll discuss it in more details a little
later, is the absolute value of the

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wave-function squared.
So this absolute value squared can be

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calculated.
Again, we don't, we don't worry too much

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about the overall coefficients when we
look at what is what appears in the

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exponential.
So, we can write this we can write this

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density as an exponential, basically from
here, minus x squared over d squared, but

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there is also another term, which is 1
over 1 plus t squared or tau squared, and

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tau here is exactly the time scale we
discussed in the beginning, which is mass

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times the delocalization length, in some
sense, d squared divided by h bar.

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So this completes the derivation of the
main result that we discussed earlier and

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also completes the first lecture.
Thank you very much and I will see you in

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class later in the week.
